Calculus: Early Transcendentals (2nd Edition)

by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard

Published by Pearson

ISBN 10: 0321947347

ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 257: 73

Answer

$x = 0$ is a critical point which yields a local maximum.

Work Step by Step

$f'(x) = −2x$, so $x = 0$ is a critical point. $f''(x) = −2$, so $f(0) = −2$ and the critical point yields a local maximum.

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