Answer
$Q = x^2(10 − x)$ or $Q = (10 − y)^2y$.
Work Step by Step
The constraint is $x + y = 10$, so we can express $y = 10 − x$ or $x = 10 − y$. Therefore the objective function can be expressed $Q = x^2(10 − x)$ or $Q = (10 − y)^2y$.
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.4 Optimization Problems - 4.4 Exercises - Page 274: 3
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