Answer
The domain of the function is $x$ ≠ $\frac{\pi}{2}$ + $k$2$\pi$
Work Step by Step
1 - $sinx$ ≠ 0
$sinx$ ≠ 1
$x$ $\ne$ $\frac{\pi}{2}$ + $k$2$\pi$
The domain of the function is $x$ ≠ $\frac{\pi}{2}$ + $k$2$\pi$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.2 - Mathematical Models: A Catalog of Essential Functions. - 1.2 Exercises - Page 33: 5
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