Answer
The sequence converges to $e^0 = 1$.
Work Step by Step
By continuity of limits, we can take the limit into the exponent of $e$. The limit of $\frac{-1}{\sqrt{n}}$ is 0 as $n \to \infty$. Hence the sequence converges to $e^0 = 1$.
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises - Page 704: 29
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