Answer
$\lim\limits_{x \to 0}f(x) = 0$
Work Step by Step
$f(x) = x^2$, if $x$ is rational
$f(x) = 0$, if $x$ is irrational
Let $g(x) = 0$ and let $h(x) = \vert x \vert $
When $x$ is close to $0$, $g(x) \leq f(x) \leq h(x)$
Also, $\lim\limits_{x \to 0}g(x) = 0$ and $\lim\limits_{x \to 0}h(x) = 0$
Therefore, by the Squeeze Theorem, $\lim\limits_{x \to 0}f(x) = 0$