Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 1 - Linear Functions - 1.1 Slopes and Equations of Lines - 1.1 Exercises - Page 13: 37

Answer

See proof

Work Step by Step

First side: Between $(-7/2,4)$ and $(-5/2,2)$: $m=\frac{2-4}{-\frac{5}{2}-(-\frac{7}{2})}=-2$ The opposing side: $(1,3)$ and $(2,1)$: $m=\frac{1-3}{2-1}=-2$ $\Rightarrow $ same slope. Likewise, we can now show the sides $(-7/2,4)$ and $(1,3)$: $m=\frac{3-4}{1-(-\frac{7}{2})}=-4.5$ as well as the side between $(-5/2,2)$ and $(2,1)$: $m=\frac{1-2}{2-(-\frac{5}{2})}=-4.5$ $\Rightarrow$ same slope. $\Rightarrow$ parallelogram.
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