Calculus with Applications (10th Edition)

by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.

Published by Pearson

ISBN 10: 0321749006

ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 113: 8

Answer

False.

Work Step by Step

$f(x)$ is not defined for real numbers x that yield 0 in the denominator. So, f is not defined for $ x=2\quad$AND $\quad x=-2.\\\\$ The statement is false.

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