Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.2 Factoring - R.2 Exercises - Page R-8: 27

Answer

$(3p-4)^2$

Work Step by Step

RECALL: $a^2 - 2ab + b^2=(a-b)^2$ The given trinomial can be written as: $=(3p)^2 - 2(3p)(4) + (4)^2$ Factor the trinomial using the formula above with $a=3p$ and $b=4$ to have: $=(3p-4)^2$
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