Answer
$4y^2\sqrt{2y}$
Work Step by Step
$\sqrt{32y^5}
\\= \sqrt{16(y^4)(2y)}
\\=4y^2\sqrt{2y}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises - Page R-28: 6
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