Answer
$6-3\sqrt{2}$
Work Step by Step
Rationalize the denominator by multiplying $2-\sqrt{2}$ to both the numerator and the denominator to have:
$=\dfrac{6}{2+\sqrt{2}} \cdot \dfrac{2-\sqrt{2}}{2-\sqrt{2}}
\\=\dfrac{12-6\sqrt{2}}{4-2}
\\=\dfrac{12-6\sqrt{2}}{2}
\\=6-3\sqrt{2}$
