Chapter 0 - Section 0.5 - Solving Polynomial Equations - Exercises - Page 29: 12

$x = \frac{d+1}{1-c}$

$x - 1 = cx + d$ $x - 1 + 1 = cx + d + 1$ $x = cx + d + 1$ $x - cx = cx +d + 1 - cx$ $x- cx = d + 1$ $x(1 - c) = d+ 1$ $x(1 - c) \times \frac{1}{1-c} = (d+ 1)\times\frac{1}{1-c}$ $x = \frac{d+1}{1-c}$