Answer
diverges to $-\infty$
Work Step by Step
1. f is a closed function (we know by Th.10.1 that it is continuous), that is, L= $\displaystyle \lim_{x\rightarrow a}f(x)$ = $f(a)$,
for all a from the domain of f.
2. evaluating: $f(-1)$, (plugging $x=-1$) , we see that $x=-1$ is NOT in the domain of f.
case 3 : recognize the determinate form $\displaystyle \frac{k}{0^{\pm}}=\pm\infty $
as $x\rightarrow-1^{-},$ (we approach -1 from the left),
the numerator approaches 2, which is positive,
and
the denominator is negative, (x is smaller than -1, more negative...).
The limit diverges to $-\infty$
