Answer
$ \displaystyle \frac{1}{6}(1.5x)^{4}+C$
Work Step by Step
$\displaystyle \int(1.5x)^{3}dx=$
Shortcut formula:
$\displaystyle \qquad\int(ax+b)^{n}dx=\frac{1}{a}\cdot \frac{(ax+b)^{n+1}}{n+1}+C \quad($if $n\neq-1)$
Apply with $ \left[\begin{array}{l}
a=1.5\\
b=0
\end{array}\right]$
$=\displaystyle \frac{1}{1.5}\cdot\frac{(1.5x)^{3+1}}{3+1}$
$= \displaystyle \frac{1}{6}(1.5x)^{4}+C$
