Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.5 - Conditional Probability and Independence - Exercises - Page 506: 9

Answer

$.5$

Work Step by Step

Since $A$ and $B$ are independent, $P(A\cap B)=P(A)*P(B)=.5*.4=.2$ We know that $P(A|B)=\frac{P(A\cap B)}{P(B)}$ $P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{.2}{.4}=.5$
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