Answer
$a_n = \sin{(\frac{n\pi}{2})}$
Work Step by Step
Our first term is $a_1 = 1$. The sequence resembles the relationship of $\sin(x)$ at evaluations of $x = n\frac{\pi}{2}$ as $n = 1, 2, 3, 4, \cdots.$ Hence:
$a_n = \sin{(\frac{n\pi}{2})}$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 11 - Infinite Sequences and Series - 11.1 Exercises - Page 724: 18
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