Answer
$ A=\sqrt[3] {36\pi V^2}$
Work Step by Step
Let $ r $ be the radius of a sphere; the surface area is $ A=4\pi r^2$ and $ r=\sqrt {\frac{A}{4\pi}}$
The volume of the sphere is given by $ V=\frac{4}{3}\pi r^3$ and $ r=\sqrt[3] {\frac{3V}{4\pi}}$
We have $\sqrt {\frac{A}{4\pi}}=\sqrt[3] {\frac{3V}{4\pi}}$ and $ A=\sqrt[3] {36\pi V^2}$
