Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.4 - Graphing with Software - Exercises 1.4 - Page 35: 31

Answer

See the graph below.

Work Step by Step

Rewrite the original equation as $x^2+2x+1+y^2-4y+4=4+4+1$ or $(x+1)^2+(y-2)^2=9$ which represents a circle centered at $(-1,2)$ with a radius $r=3$. The lower half of the circle is shown in the graph.
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