Answer
( -$\sqrt 4.5$, -$\sqrt 3.5$) and 𝛿 = 0.1213
Work Step by Step
Solve the inequality |f(x) -L| < e
|$x^{2}$ - 4| <0.5
-0.5 0;
Now we need to find the value of 𝛿>0 that places the open interval
(-2-𝛿, -2+𝛿) centered at -2 inside the interval ( -$\sqrt 4.5$, -$\sqrt 3.5$). distance between -2 and -$\sqrt 4.5$, is 0.1213 and distance between-2 and -$\sqrt 3.5$, is 0.1292. so we will take the smaller value for 𝛿, so 𝛿 = 0.1213
