Answer
$f(g(h(x)))=6x^2+1$
Work Step by Step
$f(x)=3x+4, g(x)=2x-1, h(x)=x^2$
$$f(g(h(x)))$$
$f(g(x^2))$
$f(2(x^2)-1)$
$f(2x^2-1)$
$3(2x^2-1)+4$
$6x^2-3+4$
$6x^2+1$
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