University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.6 - Inverse Functions and Logarithms - Exercises - Page 48: 4

Answer

$y=int(x)$ is not one-to-one.

Work Step by Step

*Condition for One-to-one Function (the Horizontal Line Test): The graph of function $y=f(x)$ intersects each horizontal line at most once. Looking at the graph of $y=int(x)$, we notice that the graph is actually a collection of short horizontal lines. Therefore, if we draw any horizontal lines through any short horizontal line of the given graph, it would intersect with infinite number of points there. Therefore, we conclude that $y=int(x)$ is not one-to-one.
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