University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Practice Exercises - Page 751: 62

Answer

$$\approx 1.625 \% $$

Work Step by Step

We can write as: $dA=\pi b \ da+\pi a db $ and at $(10,16)$, we have: $dA=16\pi \ da+10\pi db $ When $da=\pm 0.1,$ and $ db=\pm 0.1$ So, $dA=\pm 26(\pi) (0.1)=\pm 2.6 \pi$ The estimated change in $A$ is: $dA=\dfrac{dA}{A} \times 100=|\dfrac{2.6 \pi}{160 \ \pi} \times 100 | \approx 1.625 \% $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.