Answer
$$\lim_{\theta\to0}g(\theta)=1$$
Work Step by Step
$$g(\theta)=\frac{\sin\theta}{\theta}$$
(a) The table is shown below.
As we can see from 2 tables below, as $\theta$ gets more decimals and approaches $0$, the value of $g(\theta)$ also gets more decimals and apparently approaches $1$. So I would estimate here that $\lim_{\theta\to0}g(\theta)=1$.
(b) The graph is shown below.
Again, looking at the graph, the closer $\theta$ approaches $0$, the closer $g(\theta)$ gets to $1$.
