University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.3 - The Precise Definition of a Limit - Exercises - Page 77: 56

Answer

To satisfy the fluctuations of $I$, $R$ needs to lie in the interval $[23.5294,24.4898]$.

Work Step by Step

The exercise challenges us to find the interval of $R$ on which $I$ would be within $0.1$ amp of the value $I_0=5$. In other words, $$|I-5|\le0.1$$ We are also given the Ohm's law: $V=IR$, and $V=120$ volt. That means we can rewrite $I=120/R$. Now the inequality would become $$|\frac{120}{R}-5|\le0.1$$ To find the interval, we need to solve the inequality: $$-0.1\le\frac{120}{R}-5\le0.1$$ $$4.9\le\frac{120}{R}\le5.1$$ $$\frac{120}{4.9}\ge R\ge\frac{120}{5.1}$$ $$24.4898\ge R\ge23.5294$$ So to satisfy the fluctuations of $I$, $R$ needs to lie in the interval $[23.5294,24.4898]$.
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