Answer
$\sin 2x+\cos 3x+C$
Work Step by Step
Given: $ 2 \int (\cos 2x ) dx - 3 \int (\sin 3x) dx$
Thus, $2 \int (\cos 2x ) dx - 3 \int (\sin 3x) dx=(2)(\dfrac{1}{2}) \sin 2x -3\dfrac{1}{3}(\cot 3x)+C=\sin 2x+\cos 3x+C$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 58
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