Answer
$$15$$
Work Step by Step
We need to integrate the integral to compute the volume.
$$ \space Volume = \int_{0}^{5} (\dfrac{9}{25}) (5-z)^2 dz \\=-\dfrac{-3}{25}(5-z)^3]_{0}^{5} \\= (-\dfrac{3}{25}) (0-125) \\=15$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 6 - Section 6.1 - Volumes Using Cross-Sections - Exercises - Page 355: 12
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