Elementary Differential Equations and Boundary Value Problems 9th Edition

Published by Wiley
ISBN 10: 0-47038-334-8
ISBN 13: 978-0-47038-334-6

Chapter 1 - Introduction - 1.3 Classification of Differential Equations - Problems - Page 24: 1

Answer

The order is 2. The differential equation is linear.

Work Step by Step

The differential equation $$t^2\frac{d^2y}{dt^2} +t\frac{dy}{dt}+2y=\sin t $$ has order 2 because the second derivative $\frac{d^2y}{dt^2}$ is the highest derivative in the equation. To see it is linear, we subtract $\sin t$ from both sides to get $$t^2\frac{d^2y}{dt^2} +t\frac{dy}{dt}+2y-\sin t=0.$$ Since the left hand side is a linear function of $y$ and its derivatives, our differential equation is linear.
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