Linear Algebra: A Modern Introduction

Published by Cengage Learning
ISBN 10: 1285463242
ISBN 13: 978-1-28546-324-7

Chapter 1 - Vectors - 1.4 Applications - Exercises 1.4 - Page 54: 10

Answer

$50\sqrt{2}=70.71N$

Work Step by Step

It is given that a force of $100N$ is applied in the vertical direction, making angle of $45^{\circ}$ with the ground. We care about the horizontal component, for the lawn mower must move in the horizontal direction. $F=100\cos{45^\circ}=\frac{100}{\sqrt{2}}=50\sqrt{2}=70.71N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.