Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter P - Preliminary Concepts - Chapter P Review Exercises - Page 29: 31

Answer

a) $40^{\circ}$ b) $90^{\circ}$

Work Step by Step

To use the protractor, we subtract the smaller angle at one end of the protractor from the larger angle at the protractor. Doing this, we find: Case A: $$\angle1=40^{\circ}-0^{\circ} \\ \angle1=40^{\circ}$$ Case B: $$ \angle3 = 130^{\circ}-40^{\circ} \\ \angle3 = 90^{\circ}$$
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