Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 1 - Section 1.3 - Early Definitions and Postulates - Exercises - Page 30: 39

Answer

$\frac{1}{3}$a+$\frac{1}{2}$b

Work Step by Step

NM=NB+BM NB=a-($\frac{2}{3}$a)= $\frac{1}{3}$a BM=$\frac{1}{2}$b NM=$\frac{1}{3}$a+$\frac{1}{2}$b
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