Elementary Geometry for College Students (5th Edition)

by Alexander, Daniel C.; Koeberlein, Geralyn M.

Published by Brooks Cole

ISBN 10: 1439047901

ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 259: 35a

Answer

BF=6$\sqrt 3$

Work Step by Step

Since ABCDEF is a regular hexagon, the diagonals shown form a 30 60 90 triangle. CB=AB CB=6 BF=CB$\sqrt 3$ BF=6$\sqrt 3$

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