Answer
$9 \sqrt 3 \ in^2$
Work Step by Step
Suppose $A$ is the area and $s$ is the side of an equilateral triangle.
Now, the area of an equilateral triangle is $A=\dfrac{\sqrt 3 s^2}{4} \\=\dfrac{\sqrt 3 (6)^2}{4} \\= 9 \sqrt 3 \ in^2$
Geometry: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281159
ISBN 13:
978-0-13328-115-6
Chapter 10 - Area - Chapter Review - Page 678: 15
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