Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Entry-Level Assessment - Page xl: 25

Answer

C) $r=\frac{1}{2}\sqrt{\frac{A}{\pi}}$

Work Step by Step

To solve for a variable, isolate that variable on one side of the equation. $A=4\pi r^2$ Divide both sides by $4\pi$. $\frac{A}{4\pi}=\frac{4\pi r^2}{4\pi}$ Simplify. $\frac{A}{4\pi}=r^2$ Take the square root of each side. $\sqrt{\frac{A}{4\pi}}=\sqrt{r^2}$ Simplify. $\frac{1}{2}\sqrt{\frac{A}{\pi}}=r$
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