Answer
The argument is false due to inverse error
Work Step by Step
Let the two numbers be a and b.
∴ p is the statement that a|6 or b|6 (x|y translates to "x divides y")
and q is the statement that (a$\times$b)|6
If at least one of these two numbers is divisible by 6, then
the product of these two numbers is divisible by 6. (p → q)
Neither of these two numbers is divisible by 6 (¬p)
∴ The product of these two numbers is not divisible by 6.(¬q)
The argument follows the following logic:
p → q
¬p
∴ ¬q
Which, we know, is the inverse error
