Answer
$000111000000101010111110$
Work Step by Step
Follow the procedure given in the textbook, we have:
1$\rightarrow$0001
C$\rightarrow$1100
0$\rightarrow$0000
A$\rightarrow$1010
B$\rightarrow$1011
E$\rightarrow$1110
Juxtapose the above to get
$1C0ABE_{16}\rightarrow 000111000000101010111110_2$
