Answer
$\exists$ an integer n, such that n is divisible by 6 and n is either not divisible by 2 or n is not divisible by 3.
Work Step by Step
Recall the form of the negation of a universal conditional statement:
$~(\forall x, P(x) \rightarrow Q(x)) \equiv \exists x$ such that $(P(x) \land $ ~$Q(x))$
Recall also De Morgan's Laws for the negation of AND: ~(p$\land$q) $\equiv$ ~p $\lor$ ~q
