Answer
This statement is false. Consider $2$ and $8$
Work Step by Step
Consider $2$ and $8$. Their product is $16,$ a perfect square ($4^2$). However, neither $2$ nor $8$ are perfect squares.
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.1 - Page 163: 57
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