Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.2 - Page 168: 6

Answer

$\frac{1067429}{3330}$

Work Step by Step

$n=320.5492492492...$ $10n=3205.492492492...$ $10000n=3205492.492492492...$ $9990n=10000n-10n=3205492.492492492...-3205.492492492...=3202287$ $9990n=3202287$ $n=\frac{3202287}{9990}=\frac{1067429}{3330}$
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