Thinking Mathematically (6th Edition)

by Blitzer, Robert F.

Published by Pearson

ISBN 10: 0321867327

ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.2 Compound Statements and Connectives - Exercise Set 3.2 - Page 132: 26

Answer

$p \rightarrow \sim q$.

Work Step by Step

The statement can be translated to: if $p$ then (always) not $q$, which in logical symbols is: $p \rightarrow \sim q$.

Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.