Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 284: 23

Answer

$\frac{27}{32}$

Work Step by Step

$(\frac{3}{4})^{2}\div(\frac{3}{4}-\frac{1}{12})$ $=(\frac{3}{4}\times\frac{3}{4})\div(\frac{9}{12}-\frac{1}{12})$ $=\frac{9}{16}\div(\frac{8}{12})$ $=\frac{9}{16}\div\frac{2}{3}$ $=\frac{9}{16}\times\frac{3}{2}$ $=\frac{27}{32}$
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