Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.1 The Distance and Midpoint Formulas - 1.1 Assess Your Understanding - Page 9: 71

Answer

The estimated value of the poverty threshold for a family of four with two children under the age of $18$ in $2008$ is $21142$. The actual poverty threshold is $\$692$ off of the calculated value.

Work Step by Step

From the information, let ${{P}_{1}}=(2003,18660)$ and${{P}_{2}}=(2013,23624)$. By the midpoint formula, the coordinate of the midpoint of two points ${{P}_{1}}=(2003,18660)$ and ${{P}_{2}}=(2013,23624)$ is $\left( x,\,y \right)=\left( \frac{2003+2013}{2},\,\frac{18660+23624}{2} \right)$ $\left( x,\,y \right)=\left( \frac{4016}{2},\,\frac{42284}{2} \right)$ $\left( x,\,y \right)=\left( 2008,\,21142 \right)$ The estimated value of the poverty threshold for a family of four with two children under the age of $18$ in $2008$ is $21142$. The actual poverty threshold in $2008$ is $\$21,834$. Therefore, the error in estimation is: $=|\operatorname{Actual}\,\operatorname{value}\,-\,estimated\,value|$ $=|21834-21142|\,=\,692$ Therefore, the error in estimation is $692$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.