Answer
Answer may vary, but using the points $(320, 305)$ and $(295, 300)$ yields $y=\frac{1}{5}x+241$.
Work Step by Step
Answer may vary, for example, point 1 $(320, 305)$ and point 2 $(295, 300)$, we can get the slope as:
$\begin{align*}
m&=\dfrac{y_2-y_1}{x_2-x_1}\\
&=\dfrac{305-300}{320-295}\\
&=\frac{1}{5}
\end{align*}$
Using the point-slope form $y-y_1m(x-x_1)$ and the point $(295, 300)$, the equation of the line is:
$\begin{align*}
y-300&=\frac{1}{5}(x-295)\\
y-300&=\frac{1}{5}x-59\\
y&=\frac{1}{5}x-59+300\\
y&=\frac{1}{5}x+241
\end{align*}$
