Answer
$2\sqrt{13}.$
Work Step by Step
The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$.
Hence here: $d=\sqrt{(5-(-1))^2+(-1-3)^2}=\sqrt{36+16}=\sqrt{52}=2\sqrt{13}.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 1 - Graphs - Chapter Review - Chapter Test - Page 42: 1
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