Answer
$(x+2)^2+(y-3)^2=4^2$.
Work Step by Step
The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$.
Hence our equation: $(x+2)^2+(y-3)^2=4^2$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 1 - Graphs - Chapter Review - Review Exercises - Page 41: 11
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