Precalculus (10th Edition)

by Sullivan, Michael

Published by Pearson

ISBN 10: 0-32197-907-9

ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Review Exercises - Page 906: 4

Answer

$0$

Work Step by Step

We do what we have to according to the exercise: $$\lim_{x\to 1}(\sqrt{1-x^2})=(\sqrt{1-1^2})=(\sqrt{0})=0.$$

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