Answer
even
Work Step by Step
A function $f$ is even if $f(-x)=f(x)$, while it is odd if $f(-x)=-f9x)$.
Given $f(x)=\sqrt[3] {2x^2+1}$, we have $f(-x)=\sqrt[3] {2(-x)^2+1}=\sqrt[3] {2x^2+1}=f(x)$
Thus the function is even.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 2 - Functions and Their Graphs - 2.3 Properties of Functions - 2.3 Assess Your Understanding - Page 79: 44
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