Precalculus (6th Edition) Blitzer

by Blitzer, Robert F.

Published by Pearson

ISBN 10: 0-13446-914-3

ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Concept and Vocabulary Check - Page 626: 7

Answer

$[-\frac{\pi}{2}, \frac{\pi}{2}]$.

Work Step by Step

Here $x$ should be in the restricted domain of $sin(x)$; thus the answer is $[-\frac{\pi}{2}, \frac{\pi}{2}]$.

Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.