Answer
$$\frac{x^{26}y^6}{4}$$
Work Step by Step
\begin{align}
\\ & \frac{(2^{-1}x^{-3}y^{-1})^{-2}(2x^{-6}y^4)^{-2}(9x^3y^{-3})^0}{(2x^{-4}y^{-6})^2}\\ & = \frac{(2^2x^6y^2)(2^{-2}x^{12}y^{-8})(9^0x^0y^0)}{2^2x^{-8}y^{-12}}\\ &= \frac{2^0x^{18}y^{-6}}{2^2x^{-8}y^{-12}} \\ &= \frac{x^{18}x^8y^{-6}y^{12}}{2^2} \\ &= \frac{x^{26}y^6}{4}
\end{align}