Answer
$P=24\sqrt 5\ ft$
$A=160\ ft^2$
Work Step by Step
Step 1. Using the figure given in the Exercise and the formulas, we have for the perimeter
$P=2\times4\sqrt {20}+2\times\sqrt {80}=16\sqrt 5+8\sqrt 5=24\sqrt 5\ ft$
Step 2. The area can be found as
$A=(4\sqrt {20})(\sqrt {80})=4\sqrt {1600}=4\times40=160\ ft^2$
