Answer
$6y^n-13$
Work Step by Step
Using formulas
$(A+B)(A-B)=A^2-B^2$
and
$(A-B)^2=A^2-2AB+B^2$,
we have
$(y^n+2)(y^n-2)-(y^n-3)^2=y^{2n}-4-(y^{2n}-6y^n+9)=6y^n-13$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.4 - Polynomials - Exercise Set - Page 58: 110
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