Answer
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no (or 0)
Work Step by Step
In the quadratic formula,
$x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
The radicand, called the discriminant, $b^{2}-4ac$
could be negative, zero, or positive.
This determines whether and how many real solutions there are.
If the discriminant is negative, then we have a square root of a negative number in the formula for x,
which means that there are no such real numbers x.
In this case, the equation has no real solutions.
Fill the blank with:
no (or 0)
